(7x^2-3x-10)/(49x^2-100)

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Solution for (7x^2-3x-10)/(49x^2-100) equation:


D( x )

49*x^2-100 = 0

49*x^2-100 = 0

49*x^2-100 = 0

49*x^2 = 100 // : 49

x^2 = 100/49

x^2 = 100/49 // ^ 1/2

abs(x) = 10/7

x = 10/7 or x = -10/7

x in (-oo:-10/7) U (-10/7:10/7) U (10/7:+oo)

(7*x^2-(3*x)-10)/(49*x^2-100) = 0

(7*x^2-3*x-10)/(49*x^2-100) = 0

7*x^2-3*x-10 = 0

7*x^2-3*x-10 = 0

DELTA = (-3)^2-(-10*4*7)

DELTA = 289

DELTA > 0

x = (289^(1/2)+3)/(2*7) or x = (3-289^(1/2))/(2*7)

x = 10/7 or x = -1

(x+1)*(x-10/7) = 0

((x+1)*(x-10/7))/(49*x^2-100) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-10/7 )

x-10/7 = 0 // + 10/7

x = 10/7

x in { 10/7}

x = -1

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